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liubo4ka [24]
3 years ago
8

What is the value of 49x+2x when x equals 3

Mathematics
2 answers:
melomori [17]3 years ago
4 0

Answer:

153

Step-by-step explanation:

Rus_ich [418]3 years ago
3 0

Answer:

The answer is 153

Step-by-step explanation:

You might be interested in
From y² + 5 y - 7, subtract y² - 3 y - 4​
Vaselesa [24]

<h3>{y}^{2}  + 5y - 7 - ( {y}^{2}  - 3y - 4) \\  {y}^{2}  + 5y - 7 -  {y}^{2}  + 3y + 4 \\  {y}^{2}  - y {}^{2}  + 5y + 3y - 7 + 4 \\ 8y - 3</h3>
3 0
2 years ago
Help with graph question
Gala2k [10]
The first thing we are going to do to graph our equation is solve them for y:
For our first equation:
4x-5y=50
-5y=20-4x
y= \frac{4}{5} x-4
For our second equation:
3x+y=-4
y=-3x-4

Now, we just need to use the graphing utility to graph our equations:
y= \frac{4}{5} x-4
y=-3x-4

We can conclude that the graph of the equations is:

6 0
2 years ago
Please help
nalin [4]

Answer:

12870ways

Step-by-step explanation:

Combination has to do with selection

Total members in a tennis club = 15

number of men = 8

number of women = 7

Number of team consisting of women will be expressed as 15C7

15C7 = 15!/(15-7)!7!

15C7 = 15!/8!7!

15C7 = 15*14*13*12*11*10*9*8!/8!7!

15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C7  = 15*14*13*12*11/56

15C7 = 6,435 ways

Number of team consisting of men will be expressed as 15C8

15C8 = 15!/8!7!

15C8 = 15*14*13*12*11*10*9*8!/8!7!

15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C8 = 6,435 ways

Adding both

Total ways = 6,435 ways + 6,435 ways

Total ways = 12870ways

Hence the required number of ways is 12870ways

4 0
2 years ago
*WILL MARK BRAINLIEST*
nikdorinn [45]

Answer:

3\sqrt{5} which is approx 6.71

Step-by-step explanation:

\sqrt{45} = \sqrt{9}·\sqrt{5} = 3\sqrt{5}

4 0
2 years ago
-4x - 6y = 6<br> 4x + 6y = -4
Sloan [31]

Step-by-step explanation:

-4x - 6y = 6

4x + 6y = -4

To solve a system of equations, we can add the two equations and solve for one of the remaining variables -- let's try to eliminate the x variable when we add the two equations together.

Right now, there's a -4x term in the first equation, and a 4x term in the second equation, so if we add those together, we'll be able to eliminate the x variable altogether and solve for y.

However, when we also have a -6y term in the first equation and 6y term in the second equation, so adding these together will also eliminate the y term, leaving a 0 on the left-hand side of the equation.

If we add the two numbers on the right side of the equation, we get -2, which does not equal 0, meaning there are no solutions to this system of equations.

3 0
2 years ago
Read 2 more answers
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