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2 years ago

(Math) How do you describe a function? Must be in 3 complete sentences!

1 answer:

5 0

A function could be linear or not. Is the rate of change consistent, increasing, or decreasing? Is does the symbol have one minimum value or maximum value, or several such values?

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Simplify 16a divided by 4ab

zimovet [89]

Answer:

4b^-1

Step-by-step explanation:

16a/4 = 4a

4a/a = 4

4/b = 4b^-1

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2 years ago

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zloy xaker [14]

it the second and last answers pi(d) and 2pi(r)

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1 year ago

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Given interest of $10,510 at 12 percent for 30 days one can calculate the principal as:

gtnhenbr [62]

Answer:

$1,065,597.22

Step-by-step explanation:

Simple interest = Principal * Rate * Time/100

10,510 = P * 12 * 30/365*100

10,510*365*100 = 360P

383,615,000 = 360P

Note that the time was converted to years by dividing by 365

P = 383,615,000/360

P = $1,065,597.22

Hence the principal is $1,065,597.22

7 0

2 years ago

In parallelogram KLMN, NL=15. Identify NP. HELP PLEASE!!

adelina 88 [10]

Answer:

Step-by-step explanation:

Fact: The diagonals of a parallelogram bisect each other. If NL= 15 the NP = 1/2 NL

1/2 NL = 15/2 = 7.5.

NP = 7.5

Answer: NP = 7.5 B

7 0

2 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

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2 years ago