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Diano4ka-milaya [45]
2 years ago
10

(Math) How do you describe a function? Must be in 3 complete sentences!

Mathematics
1 answer:
Alla [95]2 years ago
5 0
A function could be linear or not. Is the rate of change consistent, increasing, or decreasing? Is does the symbol have one minimum value or maximum value, or several such values?
You might be interested in
What is -9x-(2x/-3) When x equals 7
yuradex [85]
-9x- \frac{2x}{-3}

-9*(7) -  \frac{2*7}{-3}

9*7 = 63

\frac{2*7}{-3}  =  \frac{14}{-3}

Apply the fraction  rule : \frac{a}{-b} = -  \frac{a}{b}

= - \frac{14}{3}

-63-( -\frac{14}{3} )

Apply rule  - ( - a) = a

-63+ \frac{14}{3}

Convert  element to fraction :

63 =  \frac{63}{1}

-\frac{63}{1} + \frac{14}{3}

Find the LCD 1*3 = 3

- \frac{63*3}{3}+ \frac{14}{3}

\frac{-3+63+14}{3} =  \frac{-175}{3}

<span>Apply the fraction  rule : \frac{a}{-b} = - \frac{a}{b}</span>

= - \frac{175}{3}

hope this helps!

4 0
3 years ago
Which graph represents the function f (x) = StartFraction 2 x minus 1 Over x minus 1 EndFraction?
Lubov Fominskaja [6]

The correct description of the graph:

<em>"One curve opens up and to the right in quadrant 1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>

<h3>Which graph is the graph of the given functions?</h3>

Here we have the function:

f(x) = \frac{2x - 1}{x - 1}

The graph of this function can be seen below:

Then we can see that a curve opens up on quadrant 1, and down on quadrants 2 and 3 (it pass throw quadrant 1 for a little bit).

Then the correct option is:

<em>"One curve opens up and to the right in </em><em>quadrant </em><em>1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>

<em />

If you want to learn more about rational functions:

brainly.com/question/1851758

#SPJ1

6 0
2 years ago
Read 2 more answers
Please help please thanks
Alina [70]

Answer:

A

Step-by-step explanation:

Newton's third law states that for every force, there is an equal and opposite reaction. For example, if you collide two objects together, all of the forces in the system would cancel out because energy conserved with the opposite and equal reactions.

Between two examples (2 identical billiard balls and 2 different toy cars), the easiest way to demonstrate Newton's third law is using the 2 balls, since they are identical in shape and mass. When pushing the two balls in the exact same way with the SAME force, the net force of the equation is basically 0;

F_f = F_1 + F_2 = ma - ma = 0

Therefore, A is correct.

If you pushed a toy car and a toy truck towards each other using the same force, the outcome would not be completely opposite since F = ma and masses are different. Instead, to have a completely opposite and equal reaction, the resulting direction and forces are different. The lighter car would accelerate more in the opposite direction to compensate for the lighter mass. Therefore, B is wrong because even though they are different sizes, newton's third law still happens in the resulting direction and forces, but are simply harder to explain due to so many differing factors.

C is wrong, because diameter of two objects has no correlation to the net force equations. Even if two objects have the same diameter, they could have different masses, shapes, elasticity, etc.

D is wrong, because it goes against Newton's 3rd law. Newton's 3rd law is a LAW. Meaning, it is ALWAYS true (unless in some distant future it's disproven). In any and every collision, energy is conserved in some way that net forces equal 0; either in friction, gravitational force, or resulting force, the net force is always 0.

5 0
2 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
Read 2 more answers
What is the area of this figure?
den301095 [7]

Answer:

21x20= 420

Step-by-step explanation:

5 0
2 years ago
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