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sweet-ann [11.9K]
3 years ago
5

The table below shows two equations:

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

Equation 1

Subtracting 5 from both sides we have

|2x - 3| = -1      - Since  an absolute values must be positive this equation has no solutions.

Equation 2:-

|5x + 3| - 10 = 3

|5x + 3| = 13

either 5x + 3 = 13  or 5x + 3 = -13

so x = 2   or x =  -16/5 = -3.2

The correct choice is B

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Korolek [52]

For this case we must solve the following system of equations:

3x-3y = -3\\2x-y = -5

To solve we follow the steps below:

We multiply the second equation by -3:

-6x + 3y = 15

Thus, we have the equivalent system:

3x-3y = -3\\-6x + 3y = 15

We add the equations:

3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4

We look for the value of the variable "y":

2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3

Thus, the solution of the system is given by:

(x, y): (- 4, -3)

Answer:

(x, y): (- 4, -3)

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