3 + 3/4x > = 15
3/4x > = 15 - 3
3/4x > = 12
x > = 12 / (3/4)
x > = 12 * 4/3
x > = 48/3 = 16 sessions <==
================
-p - 4p > -10
-5p > -10
p < -10/-5
p < 2 <===
===============
-3 - 6(4x + 6) > = 9
-3 - 24x - 36 > = 9
-24x - 39 > = 9
-24x > = 9 + 39
-24x > = 48
x < = -48/24
x < = -2 <===
=================
2x - 2 > = 10
2x > = 10 + 2
2x > = 12
x > = 12/2
x > = 6........so ur solution set is {6,7}
Yes, HL would be correct.
This states that if two hypotenuses are congruent (they have the same one)
and if one pair of legs are congruent,
the figure is congruent.
I hope this helps!
~cupcake
Answer: 0.36
Step-by-step explanation:
6/10 x 6.10= 36/100
Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).
Answer:
C
Step-by-step explanation:
y=1/x, the reciprocal is the same. Reciprocal would be reflected across y=x