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Rufina [12.5K]
3 years ago
6

Quick Algebra questions please :)

Mathematics
1 answer:
bezimeni [28]3 years ago
5 0
1. -4x² + 11x + 2 = 0
     x = -(11) ± √((11)² - 4(-4)(2))
                         2(-4)
     x = -11 ± √(121 + 32)
                     -8
     x = -11 ± √(153)
                  -8
     x = -11 ± 3√(17)
                 -8
     x = -11 ± 3(4.1)  
                -8
     x = -11 ± 12.3
                -8
     x = -11 + 12.3    or    x = -11 - 12.3
                -8                             -8
     x = 1.3         or          x = -23.3
           -8                                -8
     x = -0.1625       or      x = 2.9125
     x ≈ -0.2         or          x ≈ 2.9

The answer is B.

2.          4x² - 3 = 11x
    4x² - 11x - 3 = 0
    x = -(-11) ± √((-11)² - 4(4)(-3))
                         2(4)
    x = 11 ± √(121 + 48)
                      8
    x = 11 ± √(169)
                 8
    x = 11 ± 13
               8
    x = 11 + 13    or    x = 11 - 13
              8                           8
    x = 24         or       x = -2
           8                           8
   x = 3         or          x = -0.25

The answer is C.

3. g(x) = -1(x + 2)² + 5
    g(x) = -1(x + 2)(x + 2) + 5
    g(x) = -1(x(x + 2) + 2(x + 2)) + 5
    g(x) = -1(x(x) + x(2) + 2(x) + 2(2)) + 5
    g(x) = -1(x² + 2x + 2x + 4) + 5
    g(x) = -1(x² + 4x + 4) + 5
    g(x) = -1(x²) - 1(4x) - 1(4) + 5
    g(x) = -x² - 4x - 4 + 5
    g(x) = -x² - 4x + 1

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Solve the following ODE's: c) y* - 9y' + 18y = t^2
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Answer:

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

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