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Lapatulllka [165]

3 years ago

15

A map of a rectangular park has a length of 4 inches and a width olo and a width of 6 inches. It uses a scale of 1 inch for ever

y 30 miles. a. What is the actual area of the park? Show how you know.

1 answer:

Zielflug [23.3K]3 years ago

8 0

Answer:

The actual area of the park is 21,600 miles square.

Step-by-step explanation:

<u>Step 1: Calculate the area of the park</u>

<em>Area of rectangle = Length x width</em>

Length = 4 inches

Width = 6 inches

Scale factor is given as, 1 inch = 30 miles.

So, converting the length and width in miles by using the scale factor, we get

Length = 4 * 30 = 120 miles

Width = 6 * 30 = 180 miles

The formula of finding the area of an rectangle is:

<em>Area = length x width</em>

By putting the values in equation, we get

Area = 120 x 180

Area = 21,600 miles square

Therefore, the actual area of the park is 21,600 miles square.

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3 0

3 years ago

Read 2 more answers

Please give me the answers to all three I will mark u brilliant

elixir [45]

Answer:

First know the formula for the area of a circle;

<h2>A = π $r^{2}$ </h2>

Where 'π' represents pi(3.14 or 22/7), and 'r' stands for the radius being squared.

For the first problem, we can see that 12 is our <u>diameter</u>.

And to find the radius, we need to find 1/2 of the diameter (half of the diameter), so;

D/2 = R

Replace with actual values;

12/2 = 6, <u>6</u> is our <u>radius</u>.

Now we plug this into our formula:

A = π $r^{2}$

A = 3.14(6^2)

A = 3.14(36)

A = <u>113.04 centimetres</u> is the area of the circle.

For the second problem, we can see that 18 is our <u>diameter</u>.

And to convert the diameter into the radius, we do what we did to the past problem, find 1/2 of the diameter.

So;

D/2 = R

18/2 = 9, <u>9</u> is our <u>radius</u>.

Now we plug this into our formula:

A = π $r^{2}$

A = 3.14(9^2)

A = 3.14(81)

A = <u>254.34 inches</u> is the area for this circle.

For the third problem, we can see that our radius is already given, 5.

So now we just simply and easily plug this into our formula;

A = π $r^{2}$

A = 3.14(5^2)

A = 3.14(25)

A = <u>78.5 meters</u> is the area for this circle.

4 0

2 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

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sasho [114]

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