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Olegator [25]
2 years ago
13

Pleaseeeee helpppppp meeeeee

Mathematics
1 answer:
Nitella [24]2 years ago
7 0

Answer:

y=3/2-1

Step-by-step explanation:

there

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Suppose you can factor x^2 + bx + c as (x + p)(x + q). If c > 0, what could be possible values of p and q?
ad-work [718]

p could be 5 and q could be 8 this is just my guess but i think its right

3 0
2 years ago
10 + 2-x\3 = 7<br><br><br> \ = divided by<br><br> TIA!
Lemur [1.5K]
Your answer to this problem is 15


10 + 2 - 15 / 3 = 7


Hope it helped :)

8 0
3 years ago
What is the probability of rolling a "5" on a 6-sided die
topjm [15]

Answer:

1/6

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
If a represents the hypotenuse of this right triangle, which equation could you use to find the value of a?
Nitella [24]
The answer is D because they are both legs and you are looking for the hypotenuse
4 0
2 years ago
Read 2 more answers
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