This is a stupid question. The teacher who asked this needs to go back to school.
A = x⁴ - 9y²
That's going to be a number. As long as it's positive we can choose any length for our rectangle L and we can compute the width by W=A/L. So the correct answer is the dimensions are L by (x⁴ - 9y²)/L.
They don't want the correct answer. They want you to factor this expression. We'll do it, but don't believe for a second this factoring somehow constrains the possible dimensions of some rectangle.
We use the difference of two squares, a²-b² = (a+b)(a-b)
A = x⁴ - 9y² = (x²)² - (3y)² = (x²+3y)(x²-3y)
Answer: x²+3y by x²-3y
Answer:
f=35x-1 .................
We know that
<span>The formula for the area of a quadrilateral with perpendicular diagonals is
</span>A=(0.5)*(D1*D2)
A=58 in²
D1=AC=14.5 in
D2=BD=?
so
D2=2*A/D1-----------> 2*58/14.5-----------> D2=8 in
BD=D2=8 in
the answer is
BD=8 in
5+x=-9
Use the subtractive property of equality to isolate x.
5+x=-9
-5 -5
x=-14
The value that satisfies x is -14. You can check your work by substituting x as -14 and checking if the equation is satisfied.
5+x=-9
x=-14
5+(-14)=-9
5-14=-9
-9=-9
the answer is correct. Succinctly, x=-14.
Answer:
30
Step-by-step explanation:
Because its 30 trust me
