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nalin [4]
3 years ago
8

Use the graph to determine open intervals

Mathematics
1 answer:
Katarina [22]3 years ago
4 0
See, please, this decision:
a) the function is increasing if x∈(-oo;2)∪(3;4); to the additional, y∈(-oo;1)∪(0;1)4
b) the function is decreasing if x∈(2;3)∪(4;+oo); to the additional, y∈(1;0)∪(1;-oo);
c) no intervals;

(a) Select the correct choice...
A. the function is increasing on the intervals x∈(-oo;2), (3;4)
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A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 p
Alona [7]

Answer:

250 minutes of calling will cost same using both plans.

$53

Step-by-step explanation:

Please consider the complete question.

A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls.  For what amount of calling do the two plans cost the same?  What is the cost when the two plans cost the same?

Let x represent the number of call minutes.

The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is 0.12x+23.

The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is 0.14x+18.

To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.

0.14x+18=0.12x+23

0.14x-0.12x+18=0.12x-0.12x+23

0.02x+18=23

0.02x+18-18=23-18

0.02x=5

\frac{0.02x}{0.02}=\frac{5}{0.02}

x=250

Therefore, calling for 250 minutes will cost same using both plans.

Upon substituting x=250 in expression 0.14x+18, we will get:

0.14(250)+18=35+18=53

Therefore, the cost will be $53, when the two plans cost the same.

5 0
3 years ago
The temperature of a chemical compound, in degrees Celsius, changes when the compound is exposed to UV light. The table below sh
sertanlavr [38]

The temperature of the compound will follow this function: 1/8x^2+15 ( I could be wrong).


But how did I come up with this function ??

The standard of a quadratic equation is given...the x is given...the f(x) is given. Now plug these in correspondence to find the constants. The rest is algebra. If you are not getting this answer, let me see your work



4 0
3 years ago
Money Flow An investment scheme is expected to produce a continuous flow of money, starting at $1000 and increasing exponentiall
kvasek [131]

Answer:

7.14

Step-by-step explanation:

3 0
3 years ago
Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble
lesya692 [45]
The height is 33.

Set up the equation like this,

1056 = 32 h

Solve the one step equation and get 33.

Hope this helps!
6 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
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