Answer:
250 minutes of calling will cost same using both plans.
$53
Step-by-step explanation:
Please consider the complete question.
A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls. For what amount of calling do the two plans cost the same? What is the cost when the two plans cost the same?
Let x represent the number of call minutes.
The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is 
.
The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is 
.
To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.
Therefore, calling for 250 minutes will cost same using both plans.
Upon substituting in expression , we will get:
Therefore, the cost will be $53, when the two plans cost the same.
The temperature of the compound will follow this function: 1/8x^2+15 ( I could be wrong).
But how did I come up with this function ??
The standard of a quadratic equation is given...the x is given...the f(x) is given. Now plug these in correspondence to find the constants. The rest is algebra. If you are not getting this answer, let me see your work
The height is 33.
Set up the equation like this,
1056 = 32 h
Solve the one step equation and get 33.
Hope this helps!
The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation
This gives
Evaluate the products
Evaluate the like terms
So, we have
f(x) = x²+ 2/3x - 1/9
Read more about quadratic equations at
brainly.com/question/1214333
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