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Ierofanga [76]
3 years ago
11

I NEED HELPIM NO GOOD AT RATESI CANT GO ONE TILL THIS IS ANSWER

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer : The correct option is, (A) 7 hours 42 minutes

Explanation :

Average speed : It is defined as the ratio total distance to total time.

Formula used :

\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}

As per question,

Total distance traveled = 492.8 mile

Average speed = 64 mile/hour

Now put all the given values in the above formula, we get:

\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}

64mile/hour=\frac{492.8mile}{\text{Total time}}

\text{Total time}=\frac{492.8mile}{64mile/hour}

\text{Total time}=7.7hour

As we know that, 1 hour has 60 minutes.

7.7 hours

= 7 hr + 0.7 hr

= 7 hr + 0.7 × 60 min

= 7 hr + 42 min

\text{Total time}=7\text{ hour }42\text{ minute}

Therefore, the the take them to reach their destination will be, 7 hours 42 minutes.

goblinko [34]3 years ago
6 0

Answer:

I believe its d bc if you divide the distance by speed you get that

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Step-by-step explanation:

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Create a set of data with 7 values that has a mean of 30, a median of 26, a range of 50, and an interquartile range of 36.
kotykmax [81]

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3 years ago
If m< DBG=58 and mDG =74 , find mGE
mestny [16]

Answer:

Option D: mGE = 190°

Step-by-step explanation:

From the property of angles of secant and tangent lines, we have:

DBG = (mGE - mDG)/2

(That is, the angle in point B is half the difference of the larger arc by the smaller arc defined by the lines)

So, we have that:

58 = (mGE - 74)/2

2*58 = mGE - 74

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So we have that mGE is equal to 190°, correct option: D.

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3 years ago
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2 years ago
Find an equation of a line that is tangent to the graph of f and parallel to the given line. Please see picture
ivanzaharov [21]

Answer:

y = 3x - 2 (smaller y-intercept)

y = 3x + 2 (larger y-intercept)

Step-by-step explanation:

First let's write the generic equation of a line:

y = ax + b

This line needs to be parallel to the line 3x - y + 5 = 0, so it needs to have the same slope of this line.

The line 3x - y + 5 = 0 has a slope of 3, so our line has a = 3:

y = 3x + b

Now we need to find the values of b that make this line tangent to the function f(x) = x^3

Let's first find the derivative of f(x) in relation to x:

df(x)/dx = 3x^2

This derivative is the slope of the tangent line to the function for any value of x. We need a slope of 3, so:

3x^2 = 3

x^2 = 1

x = ±1

Now, to find the y-values, we have:

f(1) = 1^3 = 1

f(-1) = (-1)^3 = -1

So, using the points (1,1) and (-1,-1) in our parallel line, we have:

first line using (1,1) : 1 = 3*1 + b

b = -2

second line using (-1,-1) : -1 = -3*1 + b

b = 2

The value of b is the y-intercept of the line, so the line with smaller y-intercept is y = 3x - 2, and the line with larger y-intercept is y = 3x + 2

8 0
3 years ago
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