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3 years ago

What is 4.5231 rounded to the nearest thousandth?

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

the answe is 4.523

Step-by-step explanation:

natka813 [3]3 years ago

7 0

The Answer is: 4.523

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Estimate this product by rounding each number to one nonzero digit before multiplying: (2876)(513)(18) ASAP PLEASE

DerKrebs [107]

2876 Rounds To 3000
513 Rounds To 500
18 Rounds To 20
Then multiply:
3000x500x20= 30,000,000

Hope i helped :)

5 0

3 years ago

Solve this equation v-10=-9

andrew11 [14]

First add 10 on both sides. So it will be v = 1.

6 0

3 years ago

Read 2 more answers

Carlos saves aluminum cans to sell to the recycling center. He recently recycled 43 pounds of cans and received $23.65. How many

qwelly [4]

Answer:

$354

Step-by-step explanation:

first we need to find out how much 1 lb of can is then we can multiply that by 200 to get the answer.

so I divided 43 by 23.65 and got 1.81818181

i'll round that to $1.82 so that equals 1 lb of a can

multiply that by 200

the answer is $354

4 0

2 years ago

Select all the correct answers.

Fofino [41]

Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

6 0

3 years ago

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

2 years ago