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GaryK [48]
3 years ago
10

11. A sample of n = 25 scores has a mean of M = 68. Find the z-score for this sample: a. If it was obtained from a population wi

th μ = 60 and σ = 10. b. If it was obtained from a population with μ = 60 and σ = 20. c. If it was obtained from a population with μ = 60 and σ = 40. 12. A population forms Gravetter, Frederick J. Statistics for The Behavioral Sciences (p. 221). Cengage Learning. Kindle Edition.
Mathematics
1 answer:
storchak [24]3 years ago
3 0

Answer:

a) z-score = 4

b) z-score = 2

c) z-score = 1

Step-by-step explanation:

* Lets revise some definition to solve the problem

- The mean of the distribution of sample means is called M

- The standard deviation of the distribution of sample means is

  called σM (standard error)

- σM = σ/√n , where σ is the standard deviation and n is the sample size

- z-score = (M - μ)/σM, where μ is the mean of the population

* Lets solve the problem

∵ The sample size n = 25

∵ The sample mean M = 68

a)

∵ The mean of population μ = 60

∵ The standard deviation σ = 10

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 10/√25 = 10/5 = 2

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/2 = 8/2 = 4

* z-score = 4

b)

∵ The mean of population μ = 60

∵ The standard deviation σ = 20

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 20/√25 = 20/5 = 4

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/4 = 8/4 = 2

* z-score = 2

c)

∵ The mean of population μ = 60

∵ The standard deviation σ = 40

- Lets find σM to find z-score

∵ σM = σ/√n

∴ σM = 40/√25 = 40/5 = 8

- Lets find z-score

∵ z-score = (M - μ)/σM

∴ z-score = (68 - 60)/8 = 8/8 = 1

* z-score = 1

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Vedmedyk [2.9K]

I'll do problem 1 to get you started.

The answer to problem 1 is <u>3400 miles</u>

============================================================

Explanation for problem 1:

We're asked to find the perimeter, which is the total distance around the exterior or outside. In other words, we need to add up the four side lengths of this quadrilateral.

We'll need the distance formula to find the lengths of the slanted sides AB and BC

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Let's first find the length of segment AB

A = (x1,y1) = (0,0)

B = (x2,y2) = (400,300)

d = Length of AB

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-400)^2 + (0-300)^2}\\\\d = \sqrt{(-400)^2 + (-300)^2}\\\\d = \sqrt{160000 + 90000}\\\\d = \sqrt{250000}\\\\d = 500\\\\

The distance from A to B is 500 miles. This is the same as saying segment AB is 500 miles long.

----------------------------------------

Now find the length of segment BC

B = (x1,y1) = (400,300)

C = (x2,y2) = (-800,800)

d = length of BC

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(400-(-800))^2 + (300-800)^2}\\\\d = \sqrt{(400+800)^2 + (300-800)^2}\\\\d = \sqrt{(1200)^2 + (-500)^2}\\\\d = \sqrt{1440000 + 250000}\\\\d = \sqrt{1690000}\\\\d = 1300\\\\

----------------------------------------

The length of CD is fairly easy to find without needing the distance formula. This is because it is a vertical line. We subtract the y coordinates of C and D to get 800-0 = 800. So CD is 800 miles long.

Segment DA is a similar story. But we subtract the x coordinates. This only works for horizontal lines. DA is 800 miles long because |-800-0| = 800. Absolute value is used to make sure the distance is never negative.

----------------------------------------

To summarize everything so far, we found these four side lengths

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  • BC = 1300
  • CD = 800
  • DA = 800

The perimeter is going to be the sum of those four sides, leading to...

perimeter = sum of sides

perimeter = AB+BC+CD+DA

perimeter = 500+1300+800+800

perimeter = 3400 miles

This is the total distance traveled if you started at city A, went to B, then to C, then to D, and then finally went back to A.

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gtnhenbr [62]

Answer:

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Step-by-step explanation:

We will use the distance equation to find the answer to this problem.

D = RT

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D is distance

R is rate

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At 250 miles per hour, suppose it takes t hours to go to st. paul. Thus, we can write:

D = 250t

Now, at 200 mi per hour, it takes 1 hour longer, so the time is "t + 1", so we can write:

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We can equate both and see:

250t=200(t+1)\\250t=200t+200

Now, we solve for t first:

250t=200t+200\\250t-200t=200\\50t=200\\t=\frac{200}{50}\\t=4

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Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

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Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

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Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

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Step-by-step explanation:


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I would go for A if anything

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