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andreyandreev [35.5K]
3 years ago
9

I need help the test is time and i have 5 min left can y'all pls help pls

Mathematics
1 answer:
lesya [120]3 years ago
3 0

Answer:

divide the figure into two parts.

area of square = side²

area of square =12²

area of square =144

area pf trapezium =1/2×(a+b)×h

area of trapezium =1/2×(12+6)×12

area of trapezium =108

area of polygon=144+108=252 unit²

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352, 345, 338, ...<br> Find the 43rd term.
Artemon [7]

Answer:

Step-by-step explanation:

first term = a = 352

Common difference = d = second term - first term

                                  = 345 - 352

                                   = (-7)

nth term = a + (n-1)*d

43rd term = 352 + (43-1)*(-7)

                 = 352 + 42 *(-7)

                  = 352 - 294

                  = 58

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3 years ago
Aliyah has $24 to spend on seven pencils. After buying them she had $10. How much did each pencil cost?
Keith_Richards [23]

Your answer is $2

She spent $2 on each pencil 2 x 7 = 14 take away 14 from 24 you get 10

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Ksenya-84 [330]

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Step-by-step explanation:

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3 years ago
What is the domain of F(x) = In(x)?
jekas [21]

Answer as an inequality:  x > 0

Answer in interval notation:  (0, \infty)

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

======================================================

Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is f^{-1}(x) = \log_b(x)

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, \log_b(x) has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of \log_b(x) is x > 0 which in interval notation would be (0, \infty). This is the interval from 0 to infinity, excluding both endpoints.

------------------------

The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

\log_e(x) = \text{Ln}(x)

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.

------------------------

In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.

8 0
3 years ago
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