Answer:
-25
Step-by-step explanation:
sorry for the mistake
Point v is graphed on a number line at -6...point u is 8 units away from v....notice that it doesn't say which way....so it can go either way....so we need to find 8 units away from -6 in both directions
-6 + 8 = 2
-6 - 8 = -14
so point u can be either at 2 or at -14...ur answers are A and D
Answer:
1/200
Step-by-step explanation:
the answer is that 0.005 is 1/200
Use the Pythagorean Theorem to find the missing lengths<span> of the </span>sides<span> of a right triangle. triangle that has an opposite </span>side<span> of </span>length 3<span> and a hypotenuse of </span>length<span> 4. </span>Determining<span> all of the </span>side lengths<span>and angle measures of a right triangle is Let's look at how to do this when you're given </span>one side length<span>and </span>one<span> acute</span>
Answer:
- It is the last graph: solid line, shaded area over the line x = 2 - x/2
Explanation:
1) <u>Set the algebraigic expression that represents the combinations of sofa and pillow orders:</u>
- Number of sofas: x (given)
- Number of pillows: 2y (given, since they come in pairs)
- Number of items = number of sofas + number of pillows = x + 2y
- Minimum of 4 items in each order (given) ⇒ x + 2y ≥ 4
<u>2) Predict the graph of the inequality x + 2y ≥ 4</u>
- The border line is the equation x + 2y = 4
- You can choose two points to draw a line
- Choose the axis-intercepst:
x = 0 ⇒ 2y = 4 ⇒ y =4/2 ⇒ y = 2 ⇒ point (0,2)
y = 0 ⇒ x = 4 ⇒ point (4,0)
Then the lines goes through (0,2) and (4,0) ... [the four graphs meet this]
- The shading area is above the line because when you solve for y you get y ≥ 2 - x/2, and the line is included because the "equal to" part of the symbol (≥ means greater than or equal to).
- To state that the line is included the graph uses a continous line instead of a dotted one.
<u>3) Conclusion:</u>
That means that the correct graph is the last one: solid line, shaded area over the line y = 2 - x/2.
Note: a more detailed graph would include the fact that the items cannot be negative, i.e. x ≥ 0 and y ≥ 0, which would result in that the shaded area would be on the first quadrant.
