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2 years ago

5

When q= -4 and g=1 look at picture

1 answer:

jeka942 years ago

6 0

Answer:

-25

Step-by-step explanation:

sorry for the mistake

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HELPPPPP ASP PLZZZZZ

-Dominant- [34]

Answer:

$(f-g)(x)$

$f(x)-g(x)$

$x^{2} -6x-27-x+9$

$x^{2} -7x-18$

----------------------

$(f*g)(x)$

$=f(x)g(x)$

$(x^{2} -6x-27)(x-9)$

$=x^{3} -15x^{2}+27x+243$

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$\frac{f}{g} (x)$

$\frac{x^{2} -6x-27}{x-9}$

$\frac{(x-9)(x+3)}{x-9}$

$x+3$

-----------------------

$(f+g)(x)$

$f(x)+g(x)$

$=x^{2} -6x-27+x-9$

$=x^{2} -5x-36$

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<u>OAmalOHopeO</u>

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5 0

2 years ago

I am a multiple of 60 I am between 400 and 600 I am 40 away from a multiple of 100 who am I

EleoNora [17]

Answer:

540 is the answer i think

8 0

2 years ago

What is 7.2km/h in m/s?

lukranit [14]

Answer: 2 meters/ seconds

Step-by-step explanation

3 0

2 years ago

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Find the value of x. x√5=x^4

Kaylis [27]

Answer:

x=0, $\sqrt[6]{5}$

Decimal form,

x=0,1.30766048......

Step-by-step explanation:

x $\sqrt{5}$ = $x^{4}$

x $\sqrt{5}$ - $x^{4}$ =0

(take x as a common factor)

x( $\sqrt{5}$ - $x^{3}$ )=0

So,

x=0 and $\sqrt{5}$ - $x^{3}$ =0

for $\sqrt{5$ - $x^{3}$ =0

(add $x^{3}$ for both sides)

$\sqrt{5}$ = $x^{3}$

x= $\sqrt[3]{\sqrt[2]{5} }$ (multiply 3 by 2)

x= $\sqrt[6]{5}$

So,

x=0, $\sqrt[6]{5}$

5 0

2 years ago

Which real-world situation can be represented by the expression 12n – 5?

madam [21]

Answer:

It would be D, because you have 12 students who have tickets worth n amount, and all of them get a discount of $5.00 off. You would there have 12 times the number of tickets (n) minus $5.00 off from your discount

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers