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Salsk061 [2.6K]
3 years ago
11

Runner A crosses the starting line of a marathon and runs at an average pace of 5.6 miles per hour. Half an hour later, Runner B

crosses the starting line and runs at an average rate of 6.4 miles per hour. If the length of the marathon is 26.2 miles, which runner will finish ahead of the other? Explain.
Runner A; Runner B will not be able to catch Runner A in the time it takes Runner A to complete the 26.2 mile course.
Runner B; Runner B will catch up to runner A 3.5 hours after Runner A crosses the starting line.
Runner B; Runner B will pass Runner A and finish more than half an hour ahead of Runner A.
Runner B; Runner B will catch up to Runner A 4 hours after Runner A crosses the starting line.
Mathematics
1 answer:
marishachu [46]3 years ago
5 0
Time it took runner A to complete the marathon = 26.2 / 5.6 = 4 hrs 41 mins
Time it took runner B to complete the marathon = 26.2 / 6.4 = 4 hrs 6 mins

Time it took runner B to complete the marathon relative to when runner A started = 30 mins + 4 hrs 6 mins = 4 hrs 36 mins

Therefore, runner B will finnish ahead of runner A.

Let x be the time the two runners are at the same point, then
5.6x + 5.6(0.5) = 6.4x
6.4x - 5.6x = 2.8
0.8x = 2.8
x = 2.8/0.8 = 3.5
Therefore, runner B will catch up with runner A 3.5 hours after runner A starts the race.
<span>Runner B; Runner B will catch up to Runner A 3.5 hours after Runner A crosses the starting line.</span>

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A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.
Vlada [557]

Answer:

a)  y=12000(2)^{\frac{t}{50}}

b)  Approx. 27,569 bacteria

c)  About 103 minutes

Step-by-step explanation:

a)

This will follow exponential modelling with form of equation shown below:

y=Ab^{\frac{t}{n}}

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}

b)

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

c)

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103

After about 103 minutes, there will be 50,000 bacteria

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The number which is a perfect square is- a) 360 b)528 c) 729 d) 677​
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answer is B
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