Question

Line PQ passes through the points P(-5,-13) and Q(5,17) what is the equation of line PQ in standard form

Answer 1

Answer:

$3x - y = - 2$

Step-by-step explanation:

The given line PQ passes through the points P(-5,-13) and Q(5,17) .

Find the slope using the formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

Plug in the points to get:

$m = \frac{17 - - 13}{5 - - 5}$

$m = \frac{30}{10}$

$m = 3$

Use the point-slope formula :

$y-y_1 = m(x - x_1)$

Substitute the point (5,17)

$y - 17 = 3(x - 5)$

Expand:

$y - 17 = 3x - 15$

The standard form is when the equation is put in the form

$ax + by = c$

Regroup the terms to get:

$3x - y = - 17 + 15$

The standard form is

$3x - y = - 2$