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algol [13]
3 years ago
14

Line PQ passes through the points P(-5,-13) and Q(5,17) what is the equation of line PQ in standard form

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

3x - y =  - 2

Step-by-step explanation:

The given line PQ passes through the points P(-5,-13) and Q(5,17) .

Find the slope using the formula:

m =  \frac{y_2-y_1}{x_2-x_1}

Plug in the points to get:

m =  \frac{17 -  - 13}{5 -  - 5}

m =  \frac{30}{10}

m = 3

Use the point-slope formula :

y-y_1 = m(x - x_1)

Substitute the point (5,17)

y - 17 = 3(x - 5)

Expand:

y - 17 = 3x - 15

The standard form is when the equation is put in the form

ax + by = c

Regroup the terms to get:

3x - y =  - 17 + 15

The standard form is

3x - y =  - 2

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