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Vlad [161]
2 years ago
10

JjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjHow do you divide decimals?

Mathematics
1 answer:
Maru [420]2 years ago
4 0
Give me a decimal to divide n I will help u
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Please help me!!!! precalc question
dangina [55]

Step-by-step explanation:

1. Ampltiude is 1

The period is

\frac{2\pi}{3}

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

7 0
3 years ago
I REALLY NEED HELP im struggling please show how to do it show WORK please. no links
Oksana_A [137]

Answer:

h=3

Step-by-step explanation:

I divided -3.6 on both sides to get h by itself, and now I have h=-3.6/-10.8. combine like terms (-3.6/-10.8) and I got 3. My final answer would be h=3

6 0
2 years ago
Betty has $33 to buy plants for her greenhouse. Each plant costs $8. How
meriva

Answer:

4 plants

Step-by-step explanation:

If betty has $33 dollars and each plant is $8, than 33/8 ≈ 4

(8 * 4 is 32)

She will have one dollar left but she can't buy another plant since that's not enough.

3 0
2 years ago
Read 2 more answers
Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab
zhenek [66]

Answer:

test statistic is ≈ -0.36

p-value is  ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • sample mean driving distance (233.8 yards)
  • M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
  • s is the standard deviation (46.6 yards)
  • N is the sample size (192)

Then test statistic is z=\frac{233.8-235}{\frac{46.6}{\sqrt{192} } } =-0.3568

p-value is  0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

6 0
3 years ago
How to solve <br> -22-(6)(-9)/3
lana [24]

Answer:

-4

Step-by-step explanation:

-22-(6)(-9)/3

= -22 -(6) (-3)

= -22 +18

= -4

8 0
2 years ago
Read 2 more answers
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