A committee raised 7/9 of their target goal last year and another 1/9 of the goal this year. What fraction of their goal has bee
1 answer:
You might be interested in
- They lose 33% of games i.e 0.33
- They win 67% of games i e 0.67
So
- P(A)=0.33
- P(A')=0.67
Now
- They win from 15games=10
- They lose=5
The required probability
So probability
- 0.213(100)=21.3%
Option B