3 ways
1st way: Anthony- Gold William-Red Christopher-Green Mathew-Blue

2nd way: Anthony- Blue William-Gold Christopher-Red Mathew-Green

3rd way: Anthony-Green William-Blue Christopher-Gold Mathew-Red

7 0

3 years ago

Solve the given equation by completing the square.

Dmitriy789 [7]

Answer:

a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

Step-by-step explanation:

$x^{2} +8x = 38$

Add 16 to both sides.

$x^{2} +8x+16 = 38 + 16$

$(x+4)^{2} =54$

$x + 4 = \sqrt{54}$ or $x + 4 = -\sqrt{54}$

$x+4=3\sqrt{6}$ or $x+4=-3\sqrt{6}$

$x=-4+3\sqrt{6}$ or $x=-4-3\sqrt{6}$

Therefore, a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

6 0

3 years ago

Read 2 more answers

What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)

dybincka [34]

Answer:

amplitude; $\frac{2}{3}$

Phase shift; $\pi$ units right

Period; $\frac{2\pi}{3}$

Step-by-step explanation:

The given function is

$y=-\frac{2}{3}\cos(3t-3\pi)$

This function is of the form;

$y=A\sin (Bt+C)$

The period is given by:

$|A|=|-\frac{2}{3}|= \frac{2}{3}$

The period is given by:

$T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}$

The phase shift is given by;

$\frac{C}{B}=\frac{-\3pi}{3}=- \pi$ or $\pi$ units right.

4 0

3 years ago