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Alina [70]
3 years ago
6

The top of a glass coffee table is a circle. The circumference is 15.7 feet.

Mathematics
1 answer:
Mila [183]3 years ago
3 0

A. radius 2.5

B. area is 19.62

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How do I solve 2x+3y=7, x-y=1
Fittoniya [83]
<span>2x+3y=7
x-y=1

</span>2x+3y=7
x=1+y

2*(1+y)+3y=7
x=1+y

2+2y+3y=7
x=1+y

5y=5       |(:5)
x=1+y

y=1
x=2

CHECK:
2x+3y=7
x-y=1

2*2 + 3*1 = 7     

x-y = 1
2-1 = 1

5 0
3 years ago
Read 2 more answers
What would my GPA be? Here are my grades.
marta [7]
That is approximately, in order, a C, a C, a B, a D, an A, a B, and an A.

In grade points that is a 2, a 2, a 3, a 1, a 4, a 3, and a 4.

The average of those numbers is about 2.7, so you have a 2.7.

You can raise that by bringing up the D as it is an outlier here.
4 0
4 years ago
A pole vaulter rested a 17 foot pole against a wall. If the top of the pole hit the wall 14 feet above the ground, how far from
mart [117]

Answer:

a = √93

a ≈ 9.64

Step-by-step explanation:

We can use the Pythagorean theorem for this: a² + b² = c²

c is given as the hypotenuse, which is the pole with a length of 17 ft

c² is 17²

b is a leg with a height of 14 ft

b² = 14²

We need to find the base leg, a,  distance from the wall to the base of the pole.

Solve:

a² + 14² = 17²

a² + 196 = 289

a² = 93

a = √93

-Chetan K

7 0
2 years ago
Tell me numbersin order
Paul [167]

Part 1:-

  • cost to park of a day is= $25+$43+$61+$79 =$208

  • and the hourly rate to a paddle boat =208÷24=$8.6 per hour

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The total cost to rent the boat will be

<u>3.5</u> hours x $<u> </u><u>12</u> per hour + $ <u>5</u> =$<u>47</u>

<u>i</u><u>f</u><u> </u><u>she </u><u>spilt </u><u>cost </u><u>with </u><u>a </u><u>friend</u><u> </u><u>,</u><u>they </u><u>will </u><u>each </u><u>pay$</u><u>4</u><u>7</u><u> </u><u>÷</u><u> </u><u>2</u><u>=</u><u> </u><u>$</u><u> </u><u>2</u><u>3</u><u>.</u><u>5</u>

7 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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