A car travelled 60 km west in 1.33 h along a straight line, then returned back east for 40 km in 0.67 h. Its average velocity is
1 answer:
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Answer:
The final velocity after the collision is 0.27 m/s.
Explanation:
Given that,
Mass of tiger, m = 0.195 kg
Initial speed of tiger model, v = 0.75 m/s
Mass of another clay model, m' = 0.335 kg
Initially, second model is at rest, v' = 0
We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :
So, the final velocity after the collision is 0.27 m/s.
Answer:
U=1.44 J
Explanation:
Given that
m = 3.7 kg
K = 450 N/m
X= 0.08 m
We know that spring stored potential energy(U) and this potential energy given as
By putting the values
U=1.44 J