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Igoryamba
3 years ago
12

What is the difference between longitudinal and transverse waves? Compare and contrast the direction of their movement, movement

of a molecule through the completion of a cycle, and amplitude and wavelength measurements of each type of wave.not a factor in influencing
Physics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

Waves are periodic disturbance of a medium that transmit carrying energy but not matter.

Depending on which direction the particles oscillate, waves are divided into two types:

- Transverse waves: in these waves, the oscillations occur in a direction perpendicular to the direction of motion of the wave. Examples of transverse waves are the vibrations in a guitar string.

- Longitudinal waves: in these waves, the oscillations occur back and forth along the direction of motion of the wave. Examples of longitudinal waves are sound waves.

As a result, amplitude and wavelength are measured differently in the two types of waves. In particular:

- The amplitude in a transverse wave is measured as the distance between the equilibrium position and the maximum displacement of a particle in the wave, in the direction perpendicular to the motion of the wave. On the other hand, in a longidutinal wave this distance is measured as the maximum displacement along the direction of propagation of the wave.

- The wavelength in a transverse wave is measured as the distance between two consecutive crests (points of maximum displacement) of the wave. For a longitudinal waves, there exist no crests, but regions of highest density of the particles (compressions) and of lowest density of the particles (rarefactions), so the wavelength is measured as the distance between two consecutive regions of compressions (or rarefactions).

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A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2
SVEN [57.7K]

Answer:

K=512J

Explanation:

Since the surface is frictionless, momentum will be conserved. If the bullet of mass m_1 has an initial velocity v_{1i} and a final velocity v_{1f} and the block of mass m_2 has an initial velocity v_{2i} and a final velocity v_{2f} then the initial and final momentum of the system will be:

p_i=m_1v_{1i}+m_2v_{2i}

p_f=m_1v_{1f}+m_2v_{2f}

Since momentum is conserved, p_i=p_f, which means:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We know that the block is brought to rest by the collision, which means v_{2f}=0m/s and leaves us with:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}

which is the same as:

v_{1f}=\frac{m_1v_{1i}+m_2v_{2i}}{m_1}

Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:

v_{1f}=\frac{(0.01kg)(2000m/s)+(4kg)(-4.2m/s)}{0.01kg}=320m/s

So kinetic energy of the bullet as it emerges from the block will be:

K=\frac{mv^2}{2}=\frac{(0.01kg)(320m/s)^2}{2}=512J

6 0
4 years ago
Which statement best defines the relationship between work and energy?
alexdok [17]

The relationship between work and energy is that work can transfer energy between objects and cause a change in the form of energy.

<h3>What is energy?</h3>

Energy is simply defined as the ability to do work.

Energy possessed by any object or matter enables it to do work of various forms.

Energy can be transferred from one object to another. Also, energy can be transformed into various forms.

Therefore, the relationship between work and energy is that work can transfer energy between objects and cause a change in the form of energy.

Learn more about energy and work at: brainly.com/question/13881533

#SPJ1

5 0
2 years ago
Read 2 more answers
30.
mrs_skeptik [129]
I think the answer is B but i could be wrong
7 0
3 years ago
Read 2 more answers
A 70.0 kg base runner moving at a speed of 4.0 m/s begins his slide into second base. The coefficient of friction between his cl
Andre45 [30]

Answer:

B. 560 J

J. 1.2 m

Explanation:

v = Final velocity = 0

u = Initial velocity = 4 m/s

\mu = Coefficient of friction = 0.7

m = Mass of runner = 70 kg

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Kinetic energy is given by

K=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow K=\dfrac{1}{2}\times 70\times (0^2-4^2)\\\Rightarrow K=-560\ \text{J}

The mechanical energy lost is 560 J

Acceleration is given by

a=-\mu g\\\Rightarrow a=-0.7\times 9.81\\\Rightarrow a=-6.867\ \text{m/s}^2

From kinematic equations we get

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-4^2}{2\times -6.867}\\\Rightarrow s=1.165\approx 1.2\ \text{m}

The runner slides for 1.2 m

4 0
3 years ago
if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?
LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

<u>The complete question is written below: </u>

<u></u>

<em>In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of 1.80 m/s^{2}, it would go from rest to its top speed in 85.6 s.  </em>

<em>a) What was the speed of the vessel? </em>

<em> </em>

<em>b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute? </em>

<em></em>

<em>Calculate the answers in both meters per second and kilometers per hour</em>

<em></em>

a) The average acceleration a_{av} is expressed as:

a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t} (1)

Where:

a_{av}=1.80 m/s^{2}

\Delta V is the variation of velocity in a given time \Delta t, which is the difference between the final velocity V and the initial velocity V_{o}=0 (because it starts from rest).

\Delta t=85.6 s

Isolating V from (1):

V=a_{av}\Delta t + V_{o} (2)

V=(1.80 m/s^{2})(85.6 s) + 0 m/s (3)

V=154.08 \frac{m}{s} (4)

If 1 km=1000m and 1 h=3600 s then:

V=154.08 \frac{m}{s}=554.68 \frac{km}{h} (4)

b) Now we need to find the final velocity when \Delta t=1 min=60 s:

<em></em>

V=(1.80 m/s^{2})(60 s) + 0 m/s (5)

V=108 \frac{m}{s}=388.8 \frac{km}{h} (6)

5 0
3 years ago
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