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algol13
3 years ago
5

18. A net force of 1.0N acts on a 4.0-kg object, initially at rest, for 4.0 seconds. What is the distance the object moves durin

g the same time? Be sure to show all work to support your answer.
Physics
2 answers:
hjlf3 years ago
6 0
Acceleration = force/mass
1/4
s=ut+1/2at^2
0*4+1/2*1/4*4^2
1/2*1/4*16
1/2*4
=2
stiv31 [10]3 years ago
3 0

Answer:

Distance moved, s = 2 meters

Explanation:

It is given that,

Net force acting on object, F = 1 N

Mass of object, m = 4 kg

We have to find the distance moved by object during 4 seconds.

From Newton's second law : a=\dfrac{F}{m}

a=\dfrac{1}{4}=0.25\ m/s^2

Using second equation of motion to find distance :

s=ut+\dfrac{1}{2}at^2

s is distance, u = 0 because initially the object is at rest

s=\dfrac{1}{2}at^2

s=\dfrac{1}{2}\times 0.25\times (4)^2

s = 2 m

Hence, the distance moved by particle in 4 seconds is 2 meters.                 

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