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notsponge [240]
3 years ago
11

A tsunami is ________. A. a sea wave generated by an earthquake, landslide, or meteor impact that may destroy coastal cities tho

usands of kilometers from its source B. a sloshing of water back and forth within a lake or a bay C. a wave caused by unusually large tidal forces D. the tendency of wet, clay-rich soils to behave like a liquid during an earthquake
Physics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

A. A sea wave generated by a displacement of water

Explanation:

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S Problem Set<br> 2.) 6.4 x 109 nm to cm
anyanavicka [17]

Answer:

6.4\cdot 10^2 cm

Explanation:

First of all, let's convert from nanometres to metres, keeping in mind that

1 nm = 10^{-9} m

So we have:

6.4\cdot 10^9 nm \cdot 10^{-9} m/nm = 6.4 m

Now we can convert from metres to centimetres, keeping in mind that

1 m = 10^2 cm

So, we find:

6.4 m \cdot 10^2 cm/m = 6.4\cdot 10^2 cm

8 0
3 years ago
A vessel is filled with a liquid of density 1900 kg/m3 . There are two holes (one above the other) in the side of the vessel. Li
FromTheMoon [43]

Answer:

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity  = 9.8 m/s²

the speed at each point

v = \sqrt{2gh}  

for upper hole  v = \sqrt{2\times 9.8 \times 19}  

                         v  = 19.29 m/s

lower hole    v = \sqrt{2\times 9.8 \times 117}  

                          v = 47.88 m/s

The path for each is parabolic

x = v t

y = \dfrac{1}{2}gt^2  

y = \dfrac{1}{2}g(\dfrac{x}{v})^2  

y = \dfrac{gx^2}{2v^2}  

we get

upper hole

y = \dfrac{9.8\times x^2}{2\times 19.29^2}= 0.0132 x^2  lower hole

y= \dfrac{9.8\times x^2}{2\times 47.88^2}=0.00214x^2  y for upper hole = 80 + y for lower hole

0.0132 x^2= 98 + 0.00214 x^2

0.0082 x^2 = 98

x = 109.32 meters

110 meters is the distance where they will intersect

4 0
3 years ago
Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2
jek_recluse [69]

The orbital radius is: r=\frac{GM}{v^2}

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

\frac{GMm}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the satellite

r is the radius of the orbit

v is the speed of the satellite

Re-arranging the equation, we find:

\frac{GM}{r}=v^2\\r=\frac{GM}{v^2}

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
An above ground swimming pool of 30 ft diameter and 5 ft depth is to be filled from a garden hose (smooth interior) of length 10
STALIN [3.7K]

This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

It will take "5.1 hours" to fill the pool.

First, we will use the formula for the dynamic pressure to find out the flow speed of water:

P=\frac{1}{2}\rho v^2\\\\v=\sqrt{\frac{2P}{\rho}}

where,

v = flow speed = ?

P = Dynamic Pressure = 55 psi(\frac{6894.76\ Pa}{1\ psi}) = 379212 Pa

\rho = density of water = 1000 kg/m³

Therefore,

v=\sqrt{\frac{2(379212\ Pa)}{1000\ kg/m^3}}

v = 27.54 m/s

Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:

\frac{V}{t} = Av\\\\t =\frac{V}{Av}

where,

t = time to fill the pool = ?

A = Area of the mouth of hose = \frac{\pi (0.015875\ m)^2}{4} = 1.98 x 10⁻⁴ m²

V = Volume of the pool = (Area of pool)(depth of pool) = A(1.524 m)

V = [\frac{\pi (9.144\ m)^2}{4}][1.524\ m] = 100.1 m³

Therefore,

t = \frac{(100.1\ m^3)}{(1.98\ x\ 10^{-4}\ m^2)(27.54\ m/s)}\\\\

<u>t = 18353.5 s = 305.9 min = 5.1 hours</u>

Learn more about dynamic pressure here:

brainly.com/question/13155610?referrer=searchResults

7 0
3 years ago
Temperature is a measure of work.<br> True<br> False
Veseljchak [2.6K]
The answer is false.
5 0
3 years ago
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