Answer:
List items are usually accessed using the indexing operator.
Explanation:
Depends on the language, and what you mean with extracting? Do you mean accessing or removing?
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
Answer:
The answer is "supplierType"
Explanation:
Description of the code:
- In the given program two structure is defined, that is "supplierType and paintType", in which "supplierType" structure two-variable name and "supplierID" is defined, that datatype is "String and integer".
- In the next step, "paintType" is declared, in which "supplierType" object supplier is created, in which two string variable "color and paintID" are defined, in which "supplierType" data type is supplied.
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
