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Anettt [7]
3 years ago
15

Write a program that reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicatin

g the number of integers that follow. For coding simplicity, follow each output integer by a space, including the last one
Computers and Technology
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

Following is the program in C language :

#include <stdio.h> // header file

#define n 5 //  macro

int main() main function

{

   int a[n],k1; // variable and array declaration

   printf("Enter the element:\n");

   for(k1=0;k1<n;++k1) //iterating the loop

   {

       scanf("%d",&a[k1]);//Read the values by user

   }

   printf("Output in Reverse Order:\n");

   for(k1=n-1;k1>=0;--k1)//iterating the loop

   {

   printf(" %d ",a[k1]); //Display the values

   }

   return 0;

}

Output:

Enter the element:

4

3

45

67

89

Output in Reverse Order: 89 67 45 3 4

Explanation:

Following is the description of the program

  • Define a macro "n" with value 5 after the header file.
  • Declared an array "a" and defined the size of that array by macro i.e "n".
  • Read the value by the user by using scanf statement in the array "a"
  • Finally In the last for loop display the values of array "a" by space.

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import java.util.Scanner;

public class Looppattern {

  public static void main(String[] args) {

      Scanner sc = new Scanner(System.in);

      System.out.println("Enter how man levels you need: ");

      int levels = sc.nextInt();

      System.out.println("\n---------------Pattern A-----------------\n");

      for (int p = 1; p <= levels; p++) {

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          }

          System.out.println();

      }

      System.out.println("\n---------------Pattern B-----------------\n");

      int r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

              System.out.print(k);

          }

          r--; // decreasing levels

          System.out.println();

      }

      System.out.println("\n---------------Pattern C-----------------\n");

      for (int p = 1; p <= levels; p++) { // here incresing

          for (int k = p; k > 0; k--) { // and here decreasing pattern to

                                          // achieve our required pattern

              System.out.print(k);

          }

          System.out.println();

      }

      System.out.println("\n---------------Pattern D-----------------\n");

      r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

              System.out.print(k);

          }

          r--; // decreasing levels

          System.out.println();

      }

  }

}

Explanation:

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Answer:

The expression of this question can be given as:

Expression:

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