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yarga [219]
3 years ago
5

I need help with this, i also have a photo to help.

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

The account  A has amount $600 and B has $1600.

<u>Step-by-step explanation:</u>

The given equations are:

a+b=2200 ⇒1

0.03a+0.05b=98  or  \frac{3}{100}a+\frac{5}{100}b⇒2

Change the first equation by isolating a,

a = 2200-b. ⇒3

Apply equation 3 in 2,

\frac{3}{100}(2200-b)+\frac{5}{100}b=98.

66- \frac{3}{100} b+\frac{5}{100}b=98.

66+ \frac{2}{100} b = 98.

6600+2b=9800.

2b=9800-6600.

2b=3200.

b=1600.

Substitute b value in equation 3

a=2200-1600.

a=600.

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<h3>How to solve logarithm?</h3>

Using logarithm rule,

logₐ b - logₐ c = logₐ (b / c)

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Therefore,

log₃ 7 - log₃ 2 = log₃ (7 / 2)

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learn more on logarithm here: brainly.com/question/24515212

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