Answer:
it's option A .............
Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
Y= 3X + 1. Perpendicular means you would change the slope by flipping it and changing the sign. So the slope then becomes 3. Then you use your points to find the y-intercept by filling in the variables. 7=3(2) + B. 7=6 + B. Then subtract 6 from both sides. B=1. Then you just put your problem back into slope intercept form with your new slope and y-intercept. Y=3x + 1.
The given equation is

hence

But x cannot be zero so x=3
So the value of x is 3
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