3 years ago

Use the quadratic formula to solve -x^+27=6x

Mathematics

1 answer:

wariber [46]3 years ago

8 0

Answer:

x = -------------

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2r2 + 3s3 − r2 + 4t2 − r2 if r = −2, s = −3, and t = 5.

Elza [17]

First, simplify the expression $2r^2 + 3s^3 - r^2 + 4t^2 - r^2.$ Here you have three terms with $r^2,$ group them in the following way:

$2r^2 + 3s^3 - r^2 + 4t^2 - r^2=2r^2-r^2-r^2+3s^3+4t^2=(2r^2-r^2-r^2)+3s^3+4t^2=$

$=r^2(2-1-1)+3s^3+4t^2=3s^3+4t^2.$

Then substitute s=-3 and t=5:

$3s^3+4t^2=3\cdot (-3)^3+4\cdot 5^2=3\cdot (-27)+4\cdot 25=-81+100=19.$

Answer: 19.

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3 years ago

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Done yay !!!!!!!!!!!!!!

Alex

Adjacent, cosine again.

a = c cos B = 13 cos(16+45/60) = 13 cos(16.75) = 12.448

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3 years ago

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What is the area of 10.5 tall and 9.2 long

mihalych1998 [28]

Answer:

A=LW

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Step-by-step explanation:

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Factor the trionomial below. X2-2x-48

Murrr4er [49]

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Step-by-step explanation:

$= x {}^{2} - 2x - 48 \\ = (x -8)(x + 6)$

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