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Usimov [2.4K]
3 years ago
10

Yasmin purchased 6 heads of cabbage that each weighed  pounds. How much did the cabbage weigh all together?

Mathematics
2 answers:
Anika [276]3 years ago
8 0

Answer:

its B i think

Step-by-step explanation:

yall needa just say the answer not explain like.smh

MakcuM [25]3 years ago
5 0
The weight of each cabbage is not given.
I'll assume that each cabbage weighs p pounds.

Now, we know that Yasmin bought 6 cabbage each weighing p pounds. To know the total weight, we will simply multiply the number of cabbages by the weight of each as follows:
Total weight = 6 * p = 6p pounds

Hope this helps :)
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Answer:

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Step-by-step explanation:

4 0
2 years ago
Which of the following is a polynomial with rootsnegative square root of 5, square root of 5, and 3
Scrat [10]

Answer:

P(x) = x³ - 3x² - 5x + 15

Step-by-step explanation:

∵ The roots of the polynomial are -√5 , √5 , 3

∴ The polynomial has 3 factors:

  (x - √5) , (x + √5) , (x - 3)

∴ P(x) = (x - √5)(x + √5)(x - 3)

          = (x² + √5x - √5x - 5)(x - 3)

          = (x² - 5)(x - 3) = x³ - 3x² - 5x + 15

∴ P(x) = x³ - 3x² - 5x + 15

3 0
3 years ago
Help me :( please help me
Katena32 [7]

Answer:

22.84, 5.83

Step-by-step explanation:

Pythagoras theorem states that: a^2+b^2=c^2

So, for red triangle, it will be: 9^2+21^2=b^2

81+441=b^2

522=b^2

square root of 522=b

22.84=b

For purple one,

3^2+5^2=a^2

9+25=a^2

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7 0
2 years ago
What is the solution set of x^2+y^2=26 and x-y=6?
lubasha [3.4K]
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5 0
3 years ago
a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
3 years ago
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