To verify whether the diagonals are perpendicular to each other, we find the slope of each segment and we can see that the slopes should be opposite reciprocals of each other.This means, these segments are really perpendicular. This theorem can be verified through congruent angles present in the quadrilateral.
Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35
minus original aera
which is 5 by 7 which is 35
4a²+24a+35-35=4a²+24a
3rd option I think, can't tell which is which
Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
pages
Step-by-step explanation:
From the table, we know that Blaine can read
pages in
minutes. Therefore, Blaine can read
pages per minute. Therefore, Blaine can read
pages in
minutes. Hope this helps!