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sasho [114]
3 years ago
8

Which step is incorrect when solving the equation 2(x+9)=4(x+7)+2?

Mathematics
1 answer:
iragen [17]3 years ago
8 0

Answer:

3. 2x+18=4x+26

Step-by-step explanation:

2(x+9)=4(x+7)+2

2x+18=4x+28+2

2x+18=4x+<u>3</u><u>0</u>

<em><u>The</u></em><em><u> </u></em><em><u>step</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>error</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>solving</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>linear</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>step</u></em><em><u> </u></em><em><u>3</u></em><em><u>.</u></em>

Hope this helps ;) ❤❤❤

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3 years ago
A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the
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Then, according to the given information, we have

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Substituting the value of x from equation (i) in equations (ii) and (iii), we have

(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)

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y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Comparing the values of y from equations (iv) and (v), we get

47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.

Thus, the required number of quarters in the collection is 11.

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