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Llana [10]
3 years ago
6

The distance between two cities on a map is 4.5cm. The map scale is 1cm : 40 miles. What is the actual distance between the two

cities? please help
Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer: 180 miles

Step-by-step explanation: 1cm=40 miles. There is 4.5 so 4*40=160 and there is also half a centimeter, which is 20 miles. 160+20

Hope this helps and brainliest would be appreciated

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Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)
zheka24 [161]

The magnitude of WX is  \sqrt{29}  ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

  • X=(x_{1},y_{1},z_{1})
  • Y=(x_{2},y_{2},z_{2})

is IXYI = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ x_{1} = -2 and x_{2} = 1

∴ y_{1} = 8 and y_{2} = 4

∴ z_{1} = -3 and z_{2] = -1

- Substitute these values in the rule above

∵ IWXI = \sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}

∴ IWXI = \sqrt{29}

The magnitude of WX is  \sqrt{29}

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

8 0
3 years ago
Read 2 more answers
The difference of 28 and a number m is 3
jonny [76]

Answer:

28 - m = 3

28 - 3 = m

25 = m

Hope this helps :) mark me brainliest if you want to

8 0
3 years ago
choose all of the terms that describe the set of lines. transversal parallel lines perpendicular lines intersecting lines
Greeley [361]

Answer:

C. Perpendicular Lines

D. Intersecting Lines

Step-by-step explanation:

Intersecting lines are a pair of lines, line segments or rays are intersecting if they have a common point.

Perpendicular lines are a point where two city roads intersect.

Hope this helps. I am sorry if you get it wrong.

3 0
3 years ago
A rectangular prism has a surface area of 8 square feet. A similar rectangular prism has a surface area of 200 square feet. How
natita [175]

It would be 25 how I got that answer was I did 200 ÷ 8 and that gave me 25

7 0
3 years ago
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A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
4 years ago
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