Question

How do I solve for x and state the restriction if (a-c)/(x-a)=m

Answer 1

$\frac{a - c}{x - a} = m$

$(x - a) \frac{a - c}{x - a} = m ( x - a)$

$a - c = mx - am$

$a - c + am = mx$

$\frac{a}{m} - \frac{c}{m} + \frac{am}{m} = x$

$\frac{a - c}{m} + a = x$

Answer 2

$\frac{a-c}{x-a}=m;\ D:x\neq a\\\\m(x-a)=a-c\\\\mx-ma=a-c\\\\mx=a-c+ma\ \ \ \ /:m\neq0\\\\x=\frac{a-c+ma}{m}$