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Lyrx [107]
3 years ago
14

PLS HELP WILL GIVE BRAINLIST - Which number represents a square root of 3 (cosine (StartFraction pi Over 2 EndFraction) + I sine

(StartFraction pi Over 2 EndFraction) )?

Mathematics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

last option

Step-by-step explanation:

It converts sin, π and cos.

The answer is the last option.

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In a class, 45 students are taking the SAT exam.The number of boys is 9 more than the number of girls.How many girls and boys ar
maxonik [38]
The equation would be
g + (g + 9) = 45
2g + 9 = 45
- 9
2g = 36
÷ 2
g = 18
18 + 9 = 27
Girls: 18
Boys: 27
Hope this helps! Let me know if you have any questions :)
7 0
3 years ago
Use a Venn diagram to find the greatest common factor of the number 32
motikmotik
Idk the answers on your question
4 0
3 years ago
Need help asap please​
victus00 [196]

Answer:

z=3.3 repeating

Step-by-step explanation:

Move all terms that don't contain  z  to the right side and solve.

7 0
3 years ago
(a) The plane y + z = 13 intersects the cylinder x2 + y2 = 25 in an ellipse. Find parametric equations for the tangent line to t
klemol [59]

Answer:

Step-by-step explanation:

We have a curve (an ellipse) written as the system of equations

\begin{cases} y+z &= 13\\ x^2+y^2 &= 25\end{cases}.

And we want to calculate the tangent at the point (3,4,9).

The idea in this problem is to consider two variables as functions of the third. Usually we consider y and z as functions of x. Recall that a curve in the space can be written in parametric form in terms of only one variable. In this case we are considering the ‘‘natural’’ parametrization (x, y(x), z(x)).

Recall that the parametric equation of a line has the form

r(t)=\begin{cases} x(t) &= x_0 + v_1t \\ y(t) &= y_0 +v_2t\\ z(t) &= z_0 +v_3t \end{cases},

where (x_0,y_0,z_0) is a point on the line (in this particular case is (3,4,9)) and (v_1,v_2,v_3) is the direction vector of the line. In this case, the direction vector of the line is the tangent vector of the ellipse at the point (3,4,9).

Now, if we have the parametric equation of a curve (x, y(x), z(x)) its tangent line will have direction vector (1, y'(x), z'(x)). So, as we need to calculate the equation of the tangent line at the point (3,4,9) = (3, y(3), z(3)), we must obtain the tangent vector (1, y'(3), z'(3)). This part can be done taking implicit derivatives in the systems that defines the ellipse.

So, let us write the system as

\begin{cases} y(x)+z(x) &= 13\\ x^2+y^2(x) &= 25\end{cases}.

Then, taking implicit derivatives:

\begin{cases} y'(x)+z'(x) &= 0 \\ 2x+2y(x)y'(x) &= 0\end{cases}.

Now we substitute the values x=3 and y(3)=4, and we get the system of linear equations

\begin{cases} y'(3)+z'(3) &= 0 \\ 2\cdot 3+2\cdot 4y'(x) &= 0\end{cases},

where the unknowns are y'(3) and z'(3).

The system is

\begin{cases} y'(3)+z'(3) &= 0 \\ 6+8y'(x) &= 0\end{cases},

and its solutions are

y'(3) = -\frac{3}{4} and z'(3) = \frac{3}{4}.

Then, the direction vector of the tangent is

(1, -\frac{3}{4}, -\frac{3}{4}).

Finally, the tangent line has parametric equation

r(t)=\begin{cases} x(t) &= 3 + t \\ y(t) &= 4 -\frac{3}{4}t\\ z(t) &= 9 +\frac{3}{4}t \end{cases}

where t\in\mathbb{R}.

7 0
4 years ago
Find the slope given<br> (-3,4)&amp;(3,10)
8090 [49]

Answer:

The slope is 1

Step-by-step explanation:

y2 -y1 /x2 -x1

10-4/ 3- (-3)

6/6

which reduces to 1

8 0
3 years ago
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