What is an equation of the line that passes through the point (-5, -1) and is

Mathematics

1 answer:

Radda [10]3 years ago

3 0

Answer:

y = -4/5 x - 5

Step-by-step explanation:

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What is 50°F in degree Celsius?

zubka84 [21]

10 degrees Celsius :)

5 0

3 years ago

What is 33/84 in the simplest form

VARVARA [1.3K]

33 / 84 ( these digits divide by 3 first we get)
11 / 28 ( after this there is no number from which we can divide these numbers again so)
11 / 28 is the final answer

7 0

4 years ago

Read 2 more answers

Write y=1/6x + 7 in standard form using integers.

Alex

Write y=1/6x + 7 in standard form using integers.

A) 6x - y = 42

B) -x - 6y = 42

C) -× + 6y = 7

D) -× + 6y = 42

Answer: is d

hope it helps

8 0

3 years ago

Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.

expeople1 [14]

Rewriting the two equations:

[Supply] $p = q^2+20$
[Demand] $p=-4q^2+10q+18600$

Equilibrium price is when
Supply = Demand
$q^2+20 = -4q^2+10q+18600$
$q^2+4q^2+20-10q-18600 = 0$
$5q^2-10q-18580=0$ ⇒ Simplifying the equation by dividing each term by 5

$q^2-2q-3716=0$

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula.

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation.
$q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}$ , and $q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}$

We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
$q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97$
$q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97$

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62

4 0

3 years ago

Use linear combination to solve this problem. show your work.<br><br> 3x + 2y = -4<br> 4x - y = 13

pshichka [43]

Answer:

The solution of the system of equations is the point $(2,-5)$