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3 years ago

6

A 250mL sample of air at STP contains approximately 52.5mL of O2. What is the percentage of oxygen in the air

1 answer:

RSB [31]3 years ago

4 0

Yessirrrrrrr wee litttttttt sirrrrr

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6.201cm+7.4cm+0.68 cm+12.0cm

zimovet [89]

If you want the answer is centimeters is it going to be:
26.281 cm
If it make it easier for you to solve add 6.201 and 7.4 which will equal 13.601. Then add .68 to 13.601 which equals 14.281. Last add 12 to 14.281 which equals 26.281.

Hope this helps.

8 0

3 years ago

Question 1 (1 point)

Marizza181 [45]

Both ehhevshahahbsbdvhshs

4 0

3 years ago

46. The number of orbitals in the sub-levels increases by even numbers.<br> a. TRUE<br> b. FALSE

frosja888 [35]

Answer:

It's true.

Explanation:

In sub-energy level : number of orbitals

s : 2
p : 6
d : 10
f : 14

$.$

6 0

3 years ago

What is the temperature difference if 300 cal are used to warm water

PIT_PIT [208]

Answer:

<u>The temperature difference is</u> $\frac{300}{m} Kkg^{-1}$

Explanation:

The formula that is to used is :

Δ $Q=ms$ Δ $T$

<em>where ,</em>

<em>Δ $Q$ is the heat supplied in calories = 300cal</em>
<em> $m$ is the mass of water taken = m (assumed)</em>
<em>Δ $T$ is the change in temperature</em>
<em> $s$ is the specific heat of water = $1calK^{-1}Kg^{-1}$ </em>

ΔT :

$\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}$

6 0

3 years ago

What is the salt produced when calcium hydroxide, Ca(OH)2, reacts with phosphoric acid, H3PO4, in a neutralization reaction?

Pavel [41]

$3Ca(OH) _{2} +2H _{3} PO _{4}$ ⇒ $6H _{2} O+Ca _{3}(PO _{4}) _{2}$
Calcium phosphate. Which is your Ca3(PO4)2.

5 0

3 years ago

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