All categories

3 years ago

What is the representative particle for boron?

1 answer:

4 0

The molecule is the representative particle of molecular compounds. It is also the representative particle of diatomic elements.

<h2>I hope this helps you, have a beautiful day ✨</h2>

You might be interested in

If an atom, like a metal atom, has fewer valence electrons,

Gre4nikov [31]

Answer:

ionic bonding or covalent

Explanation:

7 0

2 years ago

What is the reasoning for the location of sodium in the periodic table

tatyana61 [14]

Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is 3s1, sodium should be in row 3 period a1.

3 0

3 years ago

Read 2 more answers

An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t

mel-nik [20]

Explanation:

The given data is as follows.

coefficient of volume expansion of glycerin ( $\beta$ ) = $5.1 \times 10^{-4} 1/^{o}C$

linear expansion coefficient of aluminum, $(\alpha_{A})$ = $23 \times 10^{-6} 1/^{o}C$

Volume = 100 $cm^{3}$

The increase in volume of the cup will be calculated as follows.

$\Delta V_{c} = V \times 3 \times \alpha \times \Delta T$

= $100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C$

= $75900 \times 10^{-6} cm^{3}$

= 0.0759 $cm^{3}$

Formula for increase in volume of glycerine is as follows.

$\Delta V_{g} = V \times \beta_{g} \times \Delta T$

= $100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C$

= 0.5610 $cm^{3}$

Therefore, volume of glycerin spilled is calculated as follows.

$\Delta V = \Delta V_{g} - \Delta V_{c}$

= (0.5610 - 0.0759) $cm^{3}$

= 0.4851 $cm^{3}$

Thus, we can conclude that 0.4851 $cm^{3}$ glycerin will spill out of the cup.

6 0

3 years ago

1. Which of these has only one component?

Phantasy [73]

1. Element
2. Sugar and window cleaner
3. Heterogeneous mixture.

8 0

3 years ago

Explain in detail what information can be learn about atoms of different elements by examining the periodic table. For the maxim

pav-90 [236]

Answer:

See below this long answer.

Explanation:

These are the main features of the periodic table that you will be able to relate with some property trends of the atoms like size, energy levels, valence electrons, electronegativity, and ionization energy.

A) Features:

1. Elements are arranged in increasing order of atomic number, i.e. number or protons.

2. Since atoms are neutrals, the number of electrons equals the number of protons, and, as result, the elements are arranged in increasing order of number of electrons.

3. The elements are arranged in 18 columns and 7 rows.

4. The rows are named period and correspond to the principal energy level (n): first row corresponds to n = 1, second row corresponds to n = 2, third to n = 3, and so on up to n = 7. The number of elements in each period are:

Period 1, n = 1, 2 elements

Period 2, n = 2, 8 elements

Period 3, n = 3, 8 elements

Period 4, n = 4, 18 elements

Period 5, n = 5, 18 elements

Period 6, n = 6, 32 elements (this includes the 14 lanthanides)

Period 6, n = 7, 32 elements (this includes the 14 lanthanides)

That makes a total of 118 elements.

5. The columns are named groups and they indicate the number of valence electrons

Group 1: 1 valence electron

Group 2: 2 valence electrons

Group 13: 3 valence electrons

Group 14: 4 valence electrons

Group 15: 5 valence electrons

Group 16: 6 valence electrons

Group 17: 7 valence electrons

Group 18: 8 valence electrons

Groups 3 through 12 includ the transition metals and due they have subshells that are not completely filled, their valence electrons vary.

More like a reference than as a rule these are the number of valence electrons for these groups.

Group 3: 3 valence electrons

Group 4: 2-4 valence electrons

Group 5: 2-5 valence electrons

Group 6: 2-6 valence electrons

Group 7: 2-7 valence electrons

Group 8: 2-3 valence electrons

Group 9: 2-3 valence electrons

Group 10: 2-3 valence electrons

Group 11: 1-2 valence electrons

Group 12: 2 valence electrons

B) Property trends

1. Atomic radius (size)

Down a period (from left to right): due to the increase of the positive charge (number of protons) while the main energy level (n) does not change, the electrons in the valence shell feel a stronger atraction to the nucleus causing that the atomic radius decrease from left to right.

Down a group (top to bottom): due to the increase of the main energy level, the outermost orbital is bigger and the atoms become bigger. Thus the trend is that the atomic radius increase when you go down a group.

2. First ionization energy

Down a period (from left to right): due to the increase of the nuclear charge (such as explained above) the greater attractive force makes that, in general, the first ionization energy increase from left to right.

Down a group (top to bottom): due to the increase in the size of the atom, , generally, the energy to remove an electron from the outermost shell, decrease.

3. Electronegativity

This is the relative ability to atract electrons in a covalent bond. It increases from left to right and from bottom to top: the most electronegative atoms is fluor.

3 0

4 years ago