None of the choices are equivalent
64/4 is 16
a is 4
b is 4
c is 2
d is 1
5x - 2 = 8x + 5.
-2 = -5x + 8x + 5
-2 = 3x +5
-7 = 3x
-7/3 = -2.3
I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
Step-by-step explanation:
f(x) = -3x + 4 and g(x) = 2,and
f(x) = g(x)
Then: -3x + 4 = 2
-3x = 2 - 4
-3x = -2
x = -2/-3
x = 2/3
Answer:
The value of x is x
Step-by-step explanation: