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3 years ago

68. If Fran can only pay $250 per month, what is the most expensive boat she can buy without a down payment?

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

Answer:

If she buys a boat without a down payment, then the affordable price is 5,700.

Step-by-step explanation:

Her bank charges 5% interest per year.

Let, payment = p,

p = 250(\frac{1-(1+\frac{0.05}{12})^-24}{\frac{0.05}{12}})

p = 5698.47

After round off p = 5700

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6) 2(n + 5) = -2<br> help i wasn’t paying attention in my google meet

bonufazy [111]

Answer: the answer is -6

2(n+5) = -2

2n + 10 = -2

2n = -2 - 10

2n = -12

2n *1/2 = -12 * 1/2 = -6

n = -6

5 0

3 years ago

Read 2 more answers

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

Can some one solve this

Roman55 [17]

Well, first you have to convert to one unit... then simplify
D:H
150m:16500cm
150m:160m
150:160
30:33
10:11

7 0

4 years ago

Sadie is saving for a new car. Below is the total amount of money in her savings account on the last day of each month. Show all

ICE Princess25 [194]

The mean is 10,724.28.

Explanation:

The mean is all of the values divided by the number of values there are.

So what you have to do is add all of the numbers and divide it by the amount of numbers there are.

10,150+10,211+10,424+10,769+10,884+11,155+11,477= 75,070.

Since there are 7 numbers, divide 75,070/7 and you get your mean, which is 10,724.28 rounded.

5 0

2 years ago

Helpppppppp will mark brainlest

Shkiper50 [21]

Answer:

-8

Step-by-step explanation:

what do you think, when you look at the examples given in the problem definition ?

don't you see the pattern, that f(x) = x+2 ?

f(1) = 1+2 = 3

f(2) = 2+2 = 4

f(3) = 3+2 = 5

so, if we follow this assumption, then

f(-10) = -10 + 2 = -8

5 0

3 years ago