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Katyanochek1 [597]
3 years ago
14

Select all solutions to the equation (2. — 4)(x + 5) = 0.

Mathematics
1 answer:
Anettt [7]3 years ago
3 0

Answer:

At, x=-5

Step-by-step explanation:

(2-4)(x+5)=-2×0

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8x?y

Step-by-step explanation:

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What is the volume?<br> 1 mm<br> 1 mm<br> 1 m
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1 × 1 × 1

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Find the HCF of 308 and 420.
Solnce55 [7]

Answer:

gcf, hcf, lcd (308; 420) = 28 = 2^2 × 7: greatest (highest) common factor (divisor), calculated. The numbers have common prime factors.

Step-by-step explanation:

use a calculator to help

4 0
3 years ago
Evaluate the following in polar and standard forms. Select all answers that apply. [3(cos(27°) isin(27°))]^5
Roman55 [17]
Using <span>De Moivre's formula
</span>
if z = a ( cos x + i sin x ) ⇒⇒⇒ ∴ z^n = a^n ( cos nx + i sin nx)

Part (1) 
∴ [ 3 (cos 27° + i sin 27°) ]⁵ = (3⁵) ( cos 5*27° + i sin 5*27°)
= 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form
=================================
Part (2)

The angle 135° in the second quadrant ⇒ sin is (+)  and cos is (-)
and its reference angle = 180° - 135° = 45°
sin 45° = cos 45°= 1/√2 = (√2)/2
∴ sin 135° = (√2)/2    and  cos 135° = -(√2)/2
∴ 243 ( cos 135° + i sin 135°) = 243 [ -(√2)/2 + i (√2)/2 ]

= - 243(√2)/2 + 243 (√2)/2 i ⇒⇒⇒⇒ standard form
===========================================
The correct answers are options (1) and (3)

option (1) ⇒⇒⇒ 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form  
option (3) ⇒⇒⇒ - 243(√2)/2 + 243 (√2)/2 i     ⇒⇒⇒⇒ standard form

7 0
4 years ago
The equation of circle having a diameter with endpoints (-2, 1) and (6, 7) is
densk [106]

Answer:

(x-2)^{2}+(y-4)^{2}=25

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-2,1)\\B(6,7)  

substitute the values

d=\sqrt{(7-1)^{2}+(6+2)^{2}}

d=\sqrt{(6)^{2}+(8)^{2}}

d=\sqrt{100}

d=10\ units

The radius is half the diameter

so

r=10/2=5\ units

step 2

Find the center of the circle

the center of the circle is the midpoint between the endpoints of the diameter

so

The center is

(\frac{-2+6}{2},\frac{1+7}{2})

(2,4)

step 3

Find the equation of the circle

The equation of the circle is

(x-h)^{2}+(y-k)^{2}=r^{2}

substitute the values

(x-2)^{2}+(y-4)^{2}=5^{2}

(x-2)^{2}+(y-4)^{2}=25

8 0
3 years ago
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