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AleksAgata [21]
2 years ago
8

A straight line ,L, passes through the points (2,9) and (3,5) Find the equation of the line L.​

Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

y-9=-4(x-2) or y=-4x-1

Step-by-step explanation:

First we must find the slope. Using the slope formula (diff y/diff x), we plug in using the given points;

(9-5)/(2-3)

=>4/-1 or just -4

Now, using the point slope formula, pick any point and plug into the formula y-y_1=m(x-x_1);

y-9=-4(x-2)

You can leave it just as this, if it asks specifically for slope-intercept form (y=mx+b) then just expand and simplify;

y-9=-4x+8

=> y=-4x-1

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What is the slope of the line that is perpendicular to the given line x-2y=10?
Anuta_ua [19.1K]

Answer: slope = 1/2

Step-by-step explanation:

X-2y=10

-2y=-x-10 subtract x from both sides

2y=x+10 divide by -1

y=<u>1</u> x + 5 Divide by 2

  2

slope = 1/2

6 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
2 years ago
(PLEASE HELP)An elevator car in a skyscraper can hold at most 15 people. For safety reasons, each car can carry a
natali 33 [55]

Answer:

70x + 25y + 4x + 4y \leqslant 1500

where x = number of adults

y = number of children

and the extra weights of 4kg of each person.

8 0
2 years ago
Joseph has 10 wooden boards, each is 2 meters in length. he needs 8 yards of wood to repair his fence and 25 feet to make shelve
Molodets [167]

Answer:

the answer is A he can complete both projects.

Step-by-step explanation:

3 0
3 years ago
H(t) = -t + 3; Find h(-5)
Anastasy [175]

Answer:

8

Step-by-step explanation:

h(t) = -t + 3;

h(-5)

Let t = -5

h(-5) = - -5 +3

       = 5+3

       = 8

7 0
3 years ago
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