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3 years ago

Please help quickly

Mathematics

1 answer:

lions [1.4K]3 years ago

4 0

Notice that 6 = 4+2,

11=6+5

19 = 11+8

30 = 19+11

Following the same pattern,

(next number) = 30 + 14 = 44

44 is the next number in the sequence 4, 6, 11, 19, 30, ...

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Read 2 more answers

How can I solve and start ?

dsp73

Ok so u have to set them equal to 180 bc they r supp lines so 1.15+x=180 sub 15 from both sides x=165
2.28+x-4=180 combine like terms 28-4=24 rewrite 24+x=180 den sub 24 from both sides x=156
I will put the rest in the comments if you still don't know

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What is the sum of the first 51 consecutive odd positive integers?

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We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

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