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kicyunya [14]
3 years ago
14

One divide by four why pluse four equals one divide by six why

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0
1 / 4y + 4 = 1 / 6y
Y= -48
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Solve for x: −2x − 4 > 8
kirill [66]

Answer:

x < -6

Step-by-step explanation:

-2x -4 > 8

-2x +4 >+4

-2x >12

/-2 > /-2

x < -6

remember to flip the inequality sign whenever you divide by a negative number :)

4 0
3 years ago
George is an artist. He wants to paint a background with congruent squares. If his canvas is 36 cm by 48 cm, what is the side le
8_murik_8 [283]

Answer:

it could be 1000 the answer

6 0
3 years ago
Read 2 more answers
Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.
SashulF [63]
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

  • <u>where a is side of the cube </u>

\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  61.44 cm^2  \\\end{gathered}

Now,

\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

3 0
2 years ago
Worth 12 points and please actually help me
Dmitrij [34]

Answer:

B = (-5, 4)

B' = (-5+3, 4-2) = (-2, 2)

6 0
3 years ago
Read 2 more answers
Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 53 ve
kari74 [83]
21 cars, 32 motorcycles.
create a system of equations using x for cars and y for motorcycles.
\left \{ {{x+y=53} \atop {4x+2y=148}} \right.
multiply the top equation by 2 to prepare for elimination method
\left \{ {{2x+2y=106} \atop {4x+2y=148}} \right.
subtract terms
\left \{ {{2x+2y=106} \atop {-4x-2y=-148}} \right.  = (-2x = -42)
divide both sides by negative 2 to solve for x
x =21
plug in x  into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32



8 0
3 years ago
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