(b⁷/4⁵)⁻³
= (4⁵/b⁷)³
= 4¹⁵/b²¹
Therefore answer is option b
Must click thanks and mark brainliest
Answer:
(1,-2) and (6, 3)
Step-by-step explanation:
Hope this helps ^-^
Answer:
Step-by-step explanation:
hope this helps u ...
Let us rewrite the expression so that the like terms are next to each other.
Combine the coefficients.
Solve the following system by Elimination:
{7 x + 3 y = 22 | (equation 1)
{4 y = 20 | (equation 2)
Divide equation 2 by 4:
{7 x + 3 y = 22 | (equation 1)
{0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 7 | (equation 1)
{0 x+y = 5 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 1 | (equation 1)
{0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 1, y = 5
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Solve the following system:
{y - 2 x = 10 | (equation 1)
{4 x - y = -14 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -14 | (equation 1)
{-(2 x) + y = 10 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 x - y = -14 | (equation 1)
{0 x+y/2 = 3 | (equation 2)
Multiply equation 2 by 2:
{4 x - y = -14 | (equation 1)
{0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -8 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -2 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = -2, y = 6
