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kumpel [21]
4 years ago
15

In a laboratory experiment, a computer determines that the time for a falling steel ball to travel the final 0.80 m before hitti

ng the floor is 0.087 s. With what velocity does the ball hit the floor?
Physics
1 answer:
Roman55 [17]4 years ago
8 0

Answer:

Vf = 9.622 m/s

Explanation:

Distance covered S=0.80m, Time t=0.087s and

g=9.81 m/s²  

Required: Final velocity Vf when it hit the floor

Sol:

We have first find Vi so

Vi=Vit + 0.5 a t2

Vi =8.768m/s

Now Vf= Vi + at

Vf = 9.622 m/s

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Find weight of 45 kg at height 800 km from earth's surface?​
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Answer:

<em>The weight is 348.4 N</em>

Explanation:

<u>Effect of the Altitude on the Acceleration of Gravity</u>

The effect of gravity decreases with altitude because greater altitudes mean greater distances from the Earth's center.

The practical formula to calculate the gravity as a function of the altitude h is:

{\displaystyle g_{h}=g_{0}\left({\frac {R_{\mathrm {e} }}{R_{\mathrm {e} }+h}}\right)^{2}}

Where go is the conventional gravitational acceleration = 9.80665\ m/s^2

R is the Earth's mean radius at the equator = 6,378 Km

h is the altitude.

At a height of h=800 Km, the acceleration of gravity is:

{\displaystyle g_{h}=9.80665 m/s^2\left(\frac {6,378 Km }{6,378 Km+800Km}}\right)^{2}}

Calculating:

g_h=7.74\ m/s^2

The weight is the product of the acceleration of gravity by the mass of the object, thus:

W=45\ Kg\cdot 7.74\ m/s^2=348.4\ N

The weight is 348.4 N

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