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3 years ago

A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?

Physics

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

Explanation:

The frequency of the wave when given it's velocity and wavelength only can be found by using the formula

$f = \frac{c}{ \lambda} \\$

where

c is the velocity of the wave in m/s

$\lambda$ is the wavelength in meters

From the question we have

c = 230 m/s

$\lambda$ = 2.1 m

$f = \frac{230}{2.1} = 109.523809... \\$

We have the final answer as

Hope this helps you

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4 years ago

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To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

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Here,

m = Order of the fringes

D = Distance between slits

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Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

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4 years ago

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Given:
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By definition,
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3 years ago

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Answer:

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