Answer:
P =18760.5 Pa
Explanation:
Given that
Volume ,V= 0.0434 m³
Mass ,m= 4.19 g = 0.00419 kg
T= 417 K
If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation
Ideal gas equation P V = m R T
p=Pressure ,V = Volume ,m =mass
T=Temperature ,R=Universal gas constant
Now by putting the values
P V = m R T
For water R= 0.466 KJ/kgK
P x 0.0434 = 0.00419 x 0.466 x 417
P =18.7605 KPa
P =18760.5 Pa
Therefore the answer is 18760.5 Pa
Answer:
I think it's claim 1 because the same mass would cause them both to either fall off or to stay there
Answer:
A.−2.1 × 10^10 N
Explanation:
Using the formula;
E = k Q1Q2/d²
Where;
E is the electrical force
k is the constant
Q1, Q2 are the two charges and
d is the distance between the two charges
Therefore;
E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²
= -2.1 x 10^10 N
Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.
Answer:
The amount of charge is "0.117 C" i.e., option A.
Explanation:
The given values are:
Force,
= 35 N
Electric field,
= 300 N/C
Charge,
q = ?
As we know,
⇒ 
On substituting the given values in the above formula, we get
⇒ 
⇒ 
⇒ 
Density = (mass) / (volume)
4,000 kg/m³ = (mass) / (0.09 m³)
(4,000 kg/m³) x (0.09 m³) = mass
mass = 360 kg
force of gravity = (mass) x (acceleration of gravity) = (360 kg) x (9.8 m/s²) = (360 x 9.8) kg-m<span>/s² </span><span>= </span>3,528 newtons .
