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Crank
3 years ago
10

Help me please hurry it up.

Mathematics
1 answer:
Katena32 [7]3 years ago
4 0

The answer is either to change the - 1 to 0, or to add + 1 to it next to the - 1.

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Help I need answers now
Juli2301 [7.4K]

Answer:

<u>The Answer in Exact Form:</u>

-3/22

<u>In Decimal Form:</u>

-0.136

Step-by-step explanation:

-\frac{3}{2}÷5\frac{1}{2}=-3/22

8 0
3 years ago
The length of a rectangular plot of land is 10 yards more than its width. If the area of the land 600 square yards , find the di
vagabundo [1.1K]
<span>Let the width of the rectangular plot of land be 'x' yards. Given that the length of the rectangular plot of land is 10 yards more than its width. So, width of the rectangular plot of land = (x + 10) yards. Also given that the area of the rectangular plot of land is 600 square yards. We know that, area of a rectangle = length * width That is, (x+10) * x = 600 x^2 + 10x = 600 x^2 + 10x - 600 = 0 x^2 + 30x - 20x -600 = 0 x(x + 30) - 20(x + 30) = 0 (x +30)(x -20) =0 Therefore, either (x + 30) = 0 or (x - 20) = 0 If x + 30 = 0, then x = -30 and If x - 20 = 0, then x = 20 Since 'x' represents the width of a rectangular plot of land it cannot be negative. Therefore, width of the rectangular plot of land = 20 yards length of the rectangular plot of land= x + 10 = 30 yards</span>
5 0
4 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
you have $200 in a savings account. each week for 8 weeks, you take out $18 for spending money. how much money is in your accoun
Furkat [3]
200 - 8 * 18 = 56
Total money - Week * Cost per week
5 0
3 years ago
Read 2 more answers
What is .5 as a fraction
NNADVOKAT [17]

Answer:

1/2 is 0.5 as a fraction


8 0
3 years ago
Read 2 more answers
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