All categories

3 years ago

What is the slope in this equation?

Mathematics

2 answers:

Elena L [17]3 years ago

6 0

Answer:

3/2 looks right to me.....

Vera_Pavlovna [14]3 years ago

6 0

Answer:

m=(3)/(2)

Step-by-step explanation:

You might be interested in

What is the solution of the following systems of equations? y = 1/2x y = -x -3

SVEN [57.7K]

Answer:

x = -2, y = -1

Step-by-step explanation:

System of Equations

Solve the system:

y = 1/2x

y = -x - 3

Multiplying the first equation by 2:

2y = x

Substituting x in the second equation:

y = -2y - 3

Adding 2y:

3y = -3

y = -3/3

y = -1

And x = 2*(-1) = -2

Solution: x = -2, y = -1

7 0

2 years ago

I need to know division

ruslelena [56]

What do you need to know? give me an equation and i'll help you solve it

4 0

3 years ago

Can anyone slove this question pls

skad [1K]

we have: -10/4 = -2.5 ⇒ -2 > -2.5 > -3

ANSWER : -2 and -3

ok done. Thank to me :>

4 0

2 years ago

Write the rule for finding the coordinates of a point’s 90⁰ clockwise rotation about the origin.

olga nikolaevna [1]

(x,y) -> (y,-x)

hope that help

4 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago