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Natalka [10]
3 years ago
8

Initially, a spinner points west. Chenille moves it clockwise 2 1/4 revolutions and then counterclockwise 3 3/4 revolutions. In

what direction does the spinner point after two moves?
Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer: East

Step-by-step explanation:

Given

A spinner initially pointing towards west is made to move 2\frac{1}{4} revolutions clockwise and 3\frac{3}{4}  revolutions counterclockwise.

After one complete revolution pointer points at the same direction.

So, the net movement of the spinner is

\Rightarrow 3\dfrac{3}{4}-2\dfrac{1}{4}\\\\\Rightarrow \dfrac{15}{4}-\dfrac{9}{4}\\\\\Rightarrow \dfrac{15-9}{4}\\\\\Rightarrow \dfrac{6}{4}\ \text{or}\ 1\dfrac{2}{4}\ \text{CCW}

That is 1 and half-revolution counter clockwise

After 1 revolution, direction is same, but after half revolution it points towards east.

The final direction is east.

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A) 45

B) 6

C) 6.7082039326

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3 years ago
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Hi there!

For these two equations, we would be using PEMDAS...

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4 0
3 years ago
How do you work this out? need help asap
Svetlanka [38]
Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

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6 0
3 years ago
When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o
Arturiano [62]
Answer: The mean increases by 3

-----------------------------------------------------------
-----------------------------------------------------------

The original data set is 
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}

The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.

The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77

If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80

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So that's why the mean increases by 3

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3 years ago
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